Adisk with a uniform positive surface charge density lies in the x-y plane, centered on the origin. the disk contains 2.5 x 10-6 c/m2 of charge, and is 7.5 cm in radius. what is the electric field at z?

E=3 x 10^4 N/c

Explanation:

The electric field strength can be found out disk with a uniform positive surface charge density by

σ= charge density

r= radius of the disk

z= position in which we have to find electric field = 15 cm

ε_0= constant ( vacuum permitivity)

putting values we get

solving we get

E=30000 N/c

E=3 x 10^4 N/c

6 cos 34, 6 sin 34 trig

the answer is ampere

the ampere is used to measure electricity. an ampere is a unit of electric current equal. a unit of measure for the flow of current in a circuit. one ampere is the amount of current flow provided when one volt of electrical pressure is applied against one ohm of resistance.