With good tires and breaks, a car traveling 50 mi/hr on dry pavement can travel 400 ft when the driver reacts to something he sees and brings the vehicle to a stop. if this is done uniformly, what is the car's acceleration?

Explanation:

Given

initial velocity

Distance traveled before stopping

using equation of

where v=final velocity

u=initial Velocity

a=acceleration

s=displacement

v=0 as car stops after travelling

negative sign indicates it is deceleration

a.

explanation:

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2