Two pellets, with charges q1 = 22 μc and q2 = 11 μc (1 μc = 10-6 c or 1 microcoulomb = 0.1 coulombs), are located 0.52 m apart.

(a) what is the electric force between them? in n(b) what mass object would experience this same force in the earth's gravitational field? in kg

8.0 N

0.82 kg

Explanation:

Given data

q₁ = 22 × 10⁻⁶ c

q₂ = 11 × 10⁻⁶ c

distance (r): 0.52 m

We can find the electrical force between these charges using he Coulomb's law.

If the same force were experienced due to the gravitational field, we could find the value of mass associated with it using Newton's second law of motion.

F = m . g

8.0 N = m . 9.8 m/s²

m = 0.82 kg

graph slopes whilst gas cools, then it is flat whilst conensation to liquid happens, the coolong liquid then graphs as a slope when it solidifies graph is flat

latent heat

it is given that trillions of microbes make up to 1% to 3% of the body mass.

let's take average of this percentage: 2%

consider the average mass of the human body as 70 kg.

then, trillions of microbes would have mass  

therefore, 100 trillion micro-organisms would weigh:

this is an approximate value and could change depending on the mass of the human body and percentage of the microbes present in it.

average mass per microorganism =