Suppose the length of the year were 365.20 days instead of 365.25 days. how often would you have a leap year? every

a. 2 years.
b. 5 years.
c. 10 years.
d. 20 years.
e. 50 years.

That day that is added every 4 years, is added to 'complete' the missing day figure. If 0.25 (1/4) is a quarter of 1:

"Leap year" equal to: 0.25 + 0.25 + 0.25 + 0.25 = 1

0.20 (1/5) would involve the 5 part of a day:

0.20 + 0.20 + 0.20 + 0.20 + 0.20 = 1

In other words, to complete that unit, it would be necessary to carry out a leap year every 5 years.

The correct answer is B.

good looking response

the total distance that martina travels that day is

(distance from home to mom's office) plus (distance from mom's office to school)

plus (distance from school to library) plus (distance from library to friend's house)

plus (distance from friend's house to martina's house).

(we don't know what any of these distance actually is.)