Consider the power dissipated in a series r–l–c circuit with r=280ω, l=100mh, c=0.800μf, v=50v, and ω=10500rad/s. the current and the voltages in this circuit are not in phase with each other. using the values given, the phase angle ϕ was found to be 73 ∘, and the current amplitude i was found to be 5.1×10−2 a . calculate the power factor and the average power to the entire circuit and to each circuit element.

0.28802

2.57162 W

14.28 W

53.55 W

6.07142 W

Explanation:

R = 280Ω

L = 100 mH

C = 0.800 μF

V = 50 V

ω = 10500rad/s

For RLC circuit impedance is given by

Power factor is given by

The power factor is 0.28802

The average power to the circuit is given by

The average power to the circuit is 2.57162 W

Power to resistor

Power to resistor is 14.28 W

Power to inductor

Power to the inductor is 53.55 W

Power to the capacitor

The power to the capacitor is 6.07142 W

increases it

scattering of light by tiny particles in air to produce the colors we see on sky, is dependent on the following factors:

(i) wavelength of light

(ii) size of the scattering particle  

(iii) distance traveled by light through the atmosphere.

according to rayleigh's law of scattering, the amount of scattering is inversely proportional to the fourth power of its wavelength. shorter the wavelength, greater is its scattering. hence violet/blue light is scattered more than red.

sun's light is a composite light ( visible light) with wavelengths in the range 400 nm (violet) to 700 nm (red). as sunlight passes through our atmosphere, the molecules of air scatter light according to their wavelengths. during sunrise and sunset, the sun's position is below the horizon. hence light from the sun travels a greater distance in the atmosphere when compared to its position a noon.

as sunlight enters the earth's atmosphere, blue light is scattered away and at the end of its journey in the sky, only red and orange wavelengths remain in the beam.

hence at sunrise and sunset, the sky appears reddish orange.