Arectangular coil of 25 loops is suspended in a field of 0.20wb/m2.the plane of coil is parallel to the direction of the field the dimensions of the coil are 15cm perpendicular to the field line and 12cm parallel to them what is the current in the coil if there is a torque of 5.4n. m acting on it

The current in the coil is 60 Ampere.

Explanation:

Given:

Number of turns in the coil is N = 25

Dimension of the coil = 15cm X 12cm

magnitude of magnetic field = 0.20T

angle in the xy plane is θ = 0 degree

torque τ = 5.4 N-m

To find:

current in the coil is i = ?

Solution:

The torque acting on the coil is given by

=>

Converting cm to m

12 cm = 0.12 m

15 cm = 0.15 m

The area of the coil is  

A = 0.12 X 0.15

A =

Substituting the values

=>

=>

=>

=>

=>

=>

=> i = 60 A

report

explanation:

answer;

d. are made mostly of liquid

explanation;

-the general   composition and structure planets includes; they have a thick gas and liquid layer covering a small,solid core. mostly the gases are hydrogen and helium atmosphere and layers of liquid hydrogen. for instance neptune and uranus are examples of the outer planets, they have a core covered by ice and ammonia.

-neptune's atmosphere is hydrogen and helium with a bit of methane so there is no oxygen to breath and the interior is made up of frozen water and ammonia with a rock and iron core. thus, there is no liquid water or solid surface to survive.