A5000 kg truck traveling at 60 m/s stops in 5 seconds. how much friction was between the truck's tires and the ground?

60000N

Explanation:

acceleration is change in velocity

a =(v-u)/t where a is acceleration u is initial velocity and v is final velocity

a = (0-60)/5 = -60/5= - 12m/s^2

here minus sign shows that body is decelerating and force is  force of friction Now f = ma here f is force of friction m is mass and a is acceleration

f= 5000×- 12= -60000N

MINUS SIGN HERE SHOWS FORCE OF FRICTION

Hence force of friction is 60000N

explanation:

v=uf/(u-f)

= 5.-10/(5+10) convex lens has negative focal length

i had this question and the answer was 3.15 miles.

martina travels from school to her mom's office. from there, she walks to school. after school, she walks to the library and then to a friends house before finally ending back at home. find martina's total distance traveled.

a) 0 miles  

b) 0.4 miles  

c) 1 mile  

d) 3.15 miles