Aproton and an electron enter perpendicular to the direction of the magnetic field. the speed of the proton is twice the speed of the electron. what is the ratio of the force experienced by the proton to the electron?

The force on the proton will be twice in comparison with the force experienced by the electron.

Explanation:

The magnetic force acting on the moving charge particle is perpendicular to the velocity as well as the magnetic field. The factors upon which the magnitude of the force is depending and proportional are as follows:

1 Magnitude of the charge particle.

2 Magnitude of the velocity of moving charge.

3 Magnitude of magnetic field.

4 Sine of angle between the velocity and magnetic field.

As far as direction is concerned, it can be find out by right hand rule.

Lets consider,

Speed of electron = Ve

Speed of proton vp= 2ve

Magnitude of the force F = qvBsin∅

Force acting  on electron Fe = qe.ve.Bsin∅

Force acting on proton Fp = qp.vp.Bsin∅

                                       Fp = -2 qe.ve.Bsin∅

                                       Fp = -2Fe

Negative sign shows the direction of Force on proton is opposite to the direction of force on electron.

the higher the current the higher the mag field around it the higher the influence on the compass