Metal 1 has a larger work function than metal 2. both are illuminated with the same short-wavelength ultraviolet light. part a do photoelectrons from metal 1 have a higher speed, a lower speed, or the same speed as photoelectrons from metal 2?

Explanation:

Einstein's equation for photoelectric effect is as follows

hυ = Φ + 1/2 mv²

hc/λ = Φ + 1/2 mv²

λ is wavelength of light used ,  Φ is work function and v is velocity of electrons ejected .

In the equation above , if λ is constant , LHS and therefore RHS will be constant .

In RHS , if work function  Φ is greater , velocity v must be lower to make RHS constant .

Therefore metal 1 having higher work function must see lower velocity of electrons or this plate must eject electrons with lower velocity.

50 inches should be the resultant vector

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .