Two crates, of mass m1 = 71 kg and m2 = 130 kg , are in contact and at rest on a horizontal surface. force f = 610 n is exerted on the 71-kg crate. the coefficient of kinetic friction is 0.18.
1. determine the acceleration of the system.
2. determine the magnitude of the force that each crate exerts on the other.

Respective answers are 1.27 m/s^2 and 90.17 N

Explanation:

Explanation requires basic knowledge of forces in physics. The solutions are attached in this response. To summarize:

- Newton's Second Law -> F = ma

- Force of friction = Fn (normal force) x µk (coefficient of kinetic friction)

- Because the surface is leveled, Fn = Fg, Fg = mg

- The crates exert the same amount of force on each other because of the rule of action // reaction (Newton's Third Law)

305.7

explanation:

density =m/v

density =917/3.00

density = 305.

approximately = 305.7

in four significant figures