If 10 calories of energy are added to 2 grams of ice at -30° c, calculate the final temperature of the ice. (notice that the specific heat of ice is different from that of water.) t. f =
-20° c
-30° c
30° c
40° c

-20°C

Explanation:

ΔQ = m c Δt

here ΔQ is heat supplied which is 10 calories , m is mass which is 2 g , c is specific heat capacity of ice which is 0.5 cal/(g C°), Δt is change in temperature which here is to be calculated.

re arranging the equation  we get

Δt = ΔQ/(mc)

   = 10/ ( 2 × 0.5)

 =  10/1

  = 10 C°

final temperature = -30 +10 = -20°C

hence option is A

  the unit of the measure =

explanation:

  the property that is quantified by the energy needed per of material to raise the temperature by one.

  si unit of energy = joule (j)

  si unit of temperature = kelvin (k)

  si unit of mass of material = kilogram (kg)

the property that is quantified by the energy needed per of material to raise the temperature by one is called specific heat.

the unit of specific heat is