Aradioactive nuclide of atomic number emits an electron, then the daughter nuclide emits a gamma ray. what is the atomic number of the resulting nuclide after both processes? a. z - 1b. z + 1c. z + 2d. z - 2

correct answer is b    Z --->Z+1

Explanation:

In the processes of radioactive decay there are three basic processes the emission of alpha particles and the emission of beta rays and the emission of ayos range

The emission of a beta ray implies the transformation of a neutral into a proton, which implies the increase of the atomic number in a unit

          Z   >  Z +1

the atomic mass does not change since the mass of the two particles is practically the same, to balance the reaction antineutrino must also be emitted

The daughter particle is in an execrated state and passes to its base state with the emission of a gamma ray that does not change its atomic number or its atomic mass.

Consequently, from the above the correct answer is b

80cm/s.

24cm/s.

53.3cm/s.