If water is leaking from a certain tank at a constant rate of 1,200 milliliters per hour, how many seconds does it take for 1 milliliter of water to leak from the tank?

It will take 3 seconds for 1 milliliters of water to leak from the tank.

Explanation:

The rate of leak = volume of water/Time

Q = V/t equation 1

making t the subject of the equation above,

t = V/Q Equation 2.

where Q = rate of leak, V = volume of water, t = time

Given: Q = 1200 milliliters per hour, V = 1 milliliters.

Substituting these values into equation 2

t = 1/1200

t = 0.00083 hours.

If  I hours = 3600 seconds,

Then, 0.00083 hours = 0.00083×3600 seconds

= 3 second.

Therefore it will take 3 seconds for 1 milliliters of water to leak from the tank.

at positions a, g kinetic energy is maximum.

at position d, potential energy is maximum.