Calculate the rotational inertia of a meter stick, with mass 0.71 kg, about an axis perpendicular to the stick and located at the 18 cm mark. (treat the stick as a thin rod.)

To solve this problem we will use the parallel axis theorem for which the inertia of a point of an object can be found through the mathematical relation:

Where

= Inertia at center of mass

m = mass

x = Displacement of axis.

Our mass is given as 0.71kg,

m = 0.71kg

Para a Stick with length (L) the Moment of Inertia of the stick about and axis passing through the center and perpendicular to stick is

The distance between center of mass to the specific location is  

So, from parallel axis theorem ,

Therefore the rotational inertia is

answer(20) psi;