Atrain traveled from station a to station b at an average speed of 80 kilometers per hour and then from station b to station c at an average speed of 60 kilometers per hour. if the train did not stop at station b, what was the average speed at which the train traveled from station a to c?
(1) the distance that the train traveled from station a to station b was 4 times the distance that train traveled from station b to station c.
(2) the amount of time it took to the train to travel from station a to station b is 3 times the amount of time that it took the train to travel from station b to station c.

1)

75 kmh⁻¹

2)

75 kmh⁻¹

Explanation:

1)

= Speed of train from station A to station B = 80 kmh⁻¹

= distance traveled from station A to station B

= time of travel between station A to station B

we know that

= distance traveled from station B to station C

= Speed of train from station B to station C = 60 kmh⁻¹

Total distance traveled is given as

Total time of travel is given as

Average speed is given as

Given that :

So

2)

= Speed of train from station A to station B = 80 kmh⁻¹

= time of travel between station A to station B

= distance traveled from station A to station B

we know that

= distance traveled from station B to station C

= Speed of train from station B to station C = 60 kmh⁻¹

= time of travel for train from station B to station C

we know that

Total distance traveled is given as

Total time of travel is given as

Average speed is given as

Given that :

So

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

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