Kim throws a beach ball up in the air. it reaches its maximum height 0.50\, \text s0.50s0, point, 50, start text, s, end text later. we can ignore air resistance. what was the beachball's velocity at the moment it was tossed into the air?

The beach ball's velocity at the moment it was tossed into the air is 4.9 m/s.

Explanation:

Given:

Time taken by the ball to reach maximum height is,

We know that, velocity of an object at the highest point is always zero. So, final velocity of the ball is,

Also, acceleration acting on the ball is always due to gravity. So, acceleration of the ball is,

The negative sign is used as acceleration is a vector and it acts in the downward direction.

Now, we have the equation of motion relating initial velocity, final velocity, acceleration and time given as:

Where, 'u' is the initial velocity.

Plug in the given values and solve for 'u'. This gives,

Therefore, the beach ball's velocity at the moment it was tossed into the air is 4.9 m/s

what experimental evidence led scientists to change from the previous model to this one?

a few of the positive particles aimed at a gold foil seemed to bounce back.

the colors of light emitted from heated atoms had very specific energies.

experiments with water vapor showed that elements combine in specific proportions.

cathode rays were bent in the same way whenever a magnet was brought near them.

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards