A1300-n crate rests on the floor. how much work is required to move it at constant speed (a)
4.0 m along the floor against a friction force of 230 n, and (b) 4.0 m vertically?

a. The amount of work that is required to move the crate at constant speed, 4.0 meters along the floor against a friction force of 230 Newton is equal to 920 Joules.

b. The amount of work that is required to move it 4.0 meters vertically is 5200 Joules.

Given the following data:

a. To determine the amount of work that is required to move it at constant speed, 4.0 meters along the floor against a friction force of 230 Newton:

According to Newton's Second Law of Motion, the net force of the crate would be equal to zero since it is moving at a constant speed. Thus, the only force acting on the crate is a force of friction in a horizontal direction.

Mathematically, the work done above is given by this formula:

Work = 920 Joules

b. To determine the amount of work that is required to move it 4.0 meters vertically:

Note: The force that must be applied to move the crate over a distance of 4.0 meters vertically must be equal to the weight of the crate.

Work = 5200 Joules

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one "light year" is the distance that light travels, through vacuum, in one julian year.   that's 365.25 days, of 24 hours each.