A70kg person jumps from a window into a fire net 20 m
below, which stretches the net 1.1m. assume that the net behaveslike
a simple sprng, and calculate how much it would stretch if thesame
person was lying in it. how much would the net stretchif the person
jumped from 50m?

0.02867 m

1.722 m

Explanation:

x = Compression of net

h = Height of jump

g = Acceleration due to gravity = 9.81 m/s²

The potential energy and the kinetic energy of the system is conserved

The spring constant of the net is 23949.3719 N

From Hooke's Law

The net would stretch 0.02867 m

If h = 50 m

From energy conservation

Solving the above equation we get

The compression of the net is 1.722 m

0 = 0.40 / 0 = 0

= 0.20 = 9.80 ⁄2 =?

=0 , = = 0.20 =0.50 0 0.40 ⁄

=0−122 =0−12(9.80 ⁄2)(0.50)2 =1.2