Aparticle is acted on by 2 torques about the origin:
has a magnitude of 2.0nm and is directed inthe positive direction
of the x axis, and
has a magnitude of 4.0nm and is directed inthe negative direction
of the y axis. in unit-vectornotation, find
where
is the angular momentum of the particleabout the origin.

We will start with the understanding that the first derivative of the angular momentum is equivalent to the torque, therefore,

Vectorially the given value can be expressed as,

This will allow us to find the magnitude of the total torque by the trigonometric properties of the vectors, for which:

Finally the angle will be given by the relation of the tangent,

Direction of 63.4° clockwise from x-direction

a charge 3q is at the origin, and a charge −2q is on the positive x axis at x=a. part a where on the x-axis would you place a third charge so it would experience no net electric force? enter an expression for the exact answer, which will involve a square-root sign. (do not enter an approximate decimal answer.)

what was the acceleration of the 2 kg cart?

⇒ 16.0 cm/s2

what was the acceleration of the 4 kg cart?

⇒ 8.1 cm/s2

what was the acceleration of the 6 kg cart?

⇒ 5.3 cm/s2