Larry's gravitational potential energy is 1870jas he sits 2.20
m above the ground in a sky diving airplane. what is larry's
gravitational potential energy when he begins tojump from the
airplane at an altitude of 923m?

Larry's  potential energy when he jump from the airplane = 784507.54 J

Explanation:

Potential Energy: This is the energy possessed by a person by virtue of it position. The S.I unit of Energy is Joules. Mathematically it is represented as,

Ep = mgh Equation 1

m = Ep/gh Equation 2

Where Ep = potential energy, m = mass of the body, g = acceleration due to gravity, h = height.

constant: g = 9.8 m/s²

When he sits 2.20 m above the ground,

Ep = 1870 J

m = 1870/(2.2×9.8)

m = 86.73 kg.

When he begins to jump from the airplane,

h = 923 m, g = 9.8 m/s² and m = 86.73 kg

Substituting these values into equation 1

Ep = 923×9.8×86.73

Ep = 784507.54 J

Therefore Larry's  potential energy when he jump from the airplane = 784507.54 J

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer