How many
kilometers per liter will a car obtain if its engine is 25percent
efficient and it encounters and average force of 1000newtons?
assume the energy content of gasoline is 40,000,000 joulesper liter
(j/l).

10 km/L

Explanation:

Given the following from question:

Efficiency of car engine = 25% = 0.25

Average force = 1000 N

Gasoline energy content = 40,000,000 J/L

therefore:

Energy utilized effectively = Efficiency of car engine * Gasoline energy content

Energy utilized effectively = 0.25 * 40,000,000 = 10,000,000 J/L

Distance obtain by car in kilometer per meter =  Energy utilized effectively/Average force

Distance obtain by car in kilometer per meter = 10,000,000/1000 = 10,000 m/L = 10 km/L

10,000 meter per liter = 10 kilo meter per liter

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