A64 kg cross-country skier glides over snow. thecoefficient
of friction between skis and snow is 0.50. assumeall the snow
beneath his skis is at 0 degrees c and that all theinternal energy
generated by friction is added to snow, whichsticks to his skis
until melted. how far would he have to skito melt 5.0 kg of
snow?

The distance traveled by the skier is 5.309 km

Solution:

As per the question:

Mass of the skier, m = 64 kg

Coefficient of friction between the ski and the snow,

Mass of snow, M = 5.0 kg

Now,

To calculate the distance, 's' traveled by the skier, in order to melt 5.0 kg of snow:

We know that:

where

= coefficient of friction

N = Normal Reaction

N = mg

Thus

                          (1)

Also,

                                 (2)  

where

= Latent Heat of fusion

Thus from eqn (1) and (2):

s = 5.309 km

im not to sure what it is

can u provide the graph and if its not possible

then i can tell u the segment where the

average time interval starts degrading is the segment where the car is slowing down