A) a boy is riding on a merry-go-round that rotates at a constant speed. if the merry-go-round makes 3.0 revolutions in 6.0 seconds. what is its angular speed in revolutions/second and in radians/second?

Explanation:

a) The merry-go-round makes 3.0 revolutions in 6.0 seconds

   Time taken for 3 revolutions = 6 s

   Time taken for 1 revolution = 6÷3 = 2 s

   That is period, T = 2 s

   We know that

   Substituting

Angular speed = 0.5 revolutions/second = 3.14 rad/s

massxgravity x heght=weightxheight= pe

4900=490xh

h=10