Abox of mass m1 = 20.0 kg is released from rest at a warehouse loading dock and slides down a 3.0 m-high frictionless chute to a waiting truck. it happens a box of m2 = 40.0 kg was left at the bottom of the chute. what is the impulse acting on m2 during the collision between the two boxes?

´To develop this problem we will use the concepts related to the conservation of momentum and the application of energy conservation equations to find the velocity of the mass after the collision, like this:

Velocity of the mass just before the collision

Therefore the momentum just before collision would be

Momentum after the collision

Since the momentum is conserved we have that

The velocity of mass after the collision is given by

Therefore the change in momentum of mass 2 is

Therefore the impulse acting on m2 during the collision between the two boxes is

ok

explanation:

i had this question and the answer was 3.15 miles.

martina travels from school to her mom's office. from there, she walks to school. after school, she walks to the library and then to a friends house before finally ending back at home. find martina's total distance traveled.

a) 0 miles  

b) 0.4 miles  

c) 1 mile  

d) 3.15 miles