Ameter stick swinging from one end oscillates with a frequency f0. what would be the frequency, in terms of f0 , if the bottom half of the stick were cut off?

To solve this problem we will proceed to define the Period of a stick, then we will define the frequency, which is the inverse of the period. We will compare the change suffered by the new length and replace that value. The Time period of meter stick is

Here,

L = Length

g = Gravity

At the same time the frequency is

Therefore the frequency in Terms of the Period is

If bottom third were cut off then the new length is

Replacing this value at the new frequency we have that,

Finally,

2b2t

explanation:

2b2t