At zion national park a loud shout produces an echo 34.50 s later from a colorful sandstone cliff. how far away is the cliff?

The cliff is 5916.75 m far

Explanation:

Echo: This is a sound heard after the reflection of sound wave from a plane surface.

v = 2x/t Equation 1

making x the subject of the equation above,

x = vt/2 Equation 2

Where v = speed of sound in air, x = distance of the cliff, t = time to produce an echo

Given: t = 34.50 s,

Constant: v = 343 m/s

Substituting these values into equation 2,

x = 343×34.5/2

x = 5916.75 m.

Thus the cliff is 5916.75 m far

answer: the exterior temperature of commercial jet planes as they leave the stratosphere and return to the ground increases steadily.

explanation:

the lower most layer of atmosphere is troposphere which extends from 0 to 12 km above the surface of the earth. the temperature initially decreases as distance is increased from the earth's surface. commercial jets fly in lower part of the stratosphere. the stratosphere extends upto 50 km. the temperature in stratosphere starts rising again due to presence of ozone which traps the uv rays.

thus, when the planes leave the stratosphere and return to the ground, the exterior temperature increases steadily.

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s