A0.500 kg block of lead is heated from 295 k to 350. k. how much heat was absorbed by the lead? (express your answer to the nearest joule

The amount of energy needed to change the temperature of a certain supstance is given in the equation:

Q = c • m • ∆T

-Q is the amount of energy in Joules

-c is the specific heat capacity, a constant value for each supstance that shows amount of energy needed to raise the temperature of 1 g of a supstance by 1 K. Its unis is J/g•K (for lead, c=0.129J/g•K)

-m is the mass of the given supstance in grams

-∆T is the change in the temperature in Kelvins. In this case it's 350-295=55K

So, now, let's calculate:

Q = 0.129J/g•K • 500g • 55K

Q = 3,547.5 J

Rounded to the nearest whole number that is 3,548 Joules

the temperature and the pressure affect solubility. temperature affects by changing the properties of the solvent. the increase in pressure increases solubility, the decrease in pressure decreases solubility.

if they have a finite resultant