Ahorse canters away from its trainer in a straight line, moving 160m away in 17s. it then turns abruptly and gallops halfwayback in 6.8s. calculate the (a) its average speed and (b) its average velocity for the entire trip, using "away from the trainer"as the positive direction.

a)10.08 m/s

b)3.36 m/s

Explanation:

Given that

distance s₁= 160 m

time t₁= 17 s

distance s₂= 80 m

time t₂ = 6.8 s

As we know that

Total distance = Total time x Average speed

s₁ + s₂ = (t₁ +  t₂ ) Vavg

Vavg=10.08 m/s

Total displacement = Total time x Average velocity

s₁ - s₂ = (t₁ +  t₂ ) Vavg

Vavg=3.36 m/s

a)10.08 m/s

b)3.36 m/s

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards