Ahorizontal force of 100 n is used to pull a crate, which weighs 500 n, at constant velocity across a horizontal floor. what is the coefficient of kinetic friction?

The coefficient of kinetic friction is 0.2.

The velocity is constant.

Therefore,

acceleration  = 0 m/s²

Net force = 0

Therefore,

100 - f = ma

100 - f = m × 0

100 - f = 0

f = 100Newton

f = μN

where

N= normal force

μ = coefficient of kinetic friction

100 = 500μ

μ = 100 / 500

μ = 0.2

read more: link

0.2

Explanation:

Horizontal force=100N

Weight of crate=500 N

We have to find the coefficient of kinetic friction.

Normal ,N=Weight=500N

Horizontal force,

Where =Horizontal force

N=Normal force

=Coefficient of kinetic friction

Substitute the values in the formula

Hence, the coefficient of kinetic friction =0.2

close lines strong magnet less close weaker