6. a force of 40 n is applied to a 6 kg box of books. if the frictional force acting on the box is 16
n, and the box was initially at rest, what is the velocity of the box 10 s later? what is the box's
displacement over the 10 s period?

V = 40 m/s^2

Explanation:

horizontal force ,

mass, m =  6kg

time, t = 10s

frictional force,

net force

                 40N - 16N = 6 x a                      (1)

in this case you apply the equation of motion

the block is at rest, initial velocity is, U = 0

final velocity is is what we are looking for, V

since U is 0 we have

a  = V/t                                          (2)

subsituting (2) into (1)

cross multiply

240 = 6 x V

divide both sides by 6

V = 40 m/s^2

i need with 1.3.2 investigate cycling o2 and co2 apex

we need to see it