Water at a gauge pressure of 3.8 atm at street level flows into an office building at a speed of 0.62 m/s through a pipe 5.3 cm in diameter. the pipe tapers down to 3.0 cm in diameter by the top floor, 18 m above, where the faucet has been left open. calculate the flow velocity and the gauge pressure in such a pipe on the top floor. assume no branch pipes and ignore viscosity.

  P₂ = 206945 Pa

Explanation:

given,

gauge pressure = 3.8 atm

1 atm = 101325 Pa

speed of flow,v₁ = 0.62 m/s

diameter of pipe,d₁ = 5.3 cm

diameter of pipe after tapering, d₂ = 3 cm

height above the ground = 18 m

Using equation of continuity

  A₁v₁ = A₂ v₂

    v₂ = 1.94 m/s

using Bernoulli's equation

  P₂ = 206945 Pa

hence, pressure of the pipe at top floor is equal to   P₂ = 206945 Pa

what was the answer?

i think its c if i'm wrong