What is the magnitude of the momentum of a 3400 kg airplane traveling at a speed of 400 miles per hour? (note that you need to convert speed to meters per second. a mile is 1600 meters.)

The momentum of the airplane = 604452 kgm/s

Explanation:

Momentum: This can be defined as the product of mass and velocity. The S.I unit of momentum is kgm/s.

Mathematically it is expressed as

M = mv Equation 1

Where, M = momentum of the air plane, m = mass of the airplane, v = velocity of the air plane.

Given: m = 3400 kg, v = 400 miles per hour

Conversion: 400(1600/3600) m/s = 177.78 m/s.

Substituting into equation 1

M = 3400(177.78)

M = 604452 kgm/s.

Thus the momentum of the airplane = 604452 kgm/s

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

beta is electron from nucleus

something from nucleus has changed, but charge must be same for cons of charge