Calculate the density of the liquid if an aluminum ball with mass of m1 = 4.10kg has an apparent mass of m2 = 1.90kg when submerged in the liquid. the density of aluminum is 2.7

The density of the liquid = 1448.78 kg/m³

Explanation:

Density: This can be defined as the ratio of mass of a body to the volume of that body. The S.I unit of density is kg/m³.

From Archimedes principle

R.d = weight in air/upthrust = density of aluminium/density of liquid

W/U= D₁/D₂ Equation 1

making D₂ the subject of the equation

D₂ = D₁(U)/W Equation 2

Where W = Weight of aluminum in air, U = upthrust, D₁ = Density of aluminum, D₂ = Density of liquid

Given: W = mg = 4.1×9.8= 40.18 N, U = Lost in weight = 9.8(4.1-1.9)

U = 21.56 N, D₁ = 2.7 g/cm³ = 2700 kg/m³

Substituting into equation 2

D₂ = 2700(21.56)/40.18

D₂ = 1448.78 kg/m³

Thus the density of the liquid = 1448.78 kg/m³

r=rho l/a where a is the area, l is the length and rho is resistivity so the greater the area the lesser the resistance thats why the earth pin is thicker bcos current follow the shortest path, so less resistive .

the device is called “ rocket engine”