Aglass of water sits on a scale. the scale reads 4.78 n. a steel bolt weighs 2.07 n. the density of steel is 7.86 g/cm3. we tie the bolt to a string and lower the bolt into the glass of water so that the bolt is fully submerged in the water but is not touching the bottom or side of the glass.

The weight of water weight is 5.043 N.

Explanation:

Given that,

Force = 4.78 N

Weight of steel bolt = 2.07 N

Density of steel = 7.86 g/cm³

Suppose determine how much does the glass of water weight.

We need to calculate the volume of bolt

Using formula of density

Put the value into the formula

We need to calculate the force on bolt

Using buoyant force

Put the value into the formula

We need to calculate the new weight of glass of water

Using formula for weight of glass of water

Put the value into the formula

Hence, The weight of water weight is 5.043 N.

the old price per ounce is c/4.

the new price per ounce is c/3.6.

the ratio of the old price to the new one is

(c/4)/(c/3.6) = (c/c)×(3.6/4) = 0.9 . . = 9/10 . . "nine tenths" in either form