Apositively charged particle 1 is at the origin of a cartesian coordinate system, and there are no other charged objects nearby. you need the electric field magnitude at the position (1.00 nm , 8.00 nm ) to be zero, so that no electric force is exerted on any charged object placed at that location.

where would you need to place particle 2 if it carried the same charge as particle 1?

P=(2 nm, 8mn)

Explanation:

Given :

Position of positively charged particle at origin,

Position of desired magnetic field,

Magnitude of desired magnetic field,

Let q be the positive charge magnitude placed at origin.

We know the distance between the two Cartesian points is given as:

For the electric field effect to be zero at point D we need equal and opposite field at the point.

as we know that the electric field lines emerge radially outward of a positive charge so the second charge will be at equally opposite side of the  given point.

assuming that the second charge is placed at (x,y) nano-meters.

Therefore,

and

we need to know the time interval during which the force acts. impulse of force = momentum change

ok

explanation: