When spiking a volleyball, a player changes the velocity of the ball from 4.2m/s to -24m/s along a certain direction. if the impulse delivered to the ball by the player is -9.3kg . m/s, what is the mass of the volleyball?

The momentum is equal to the delivered impulse. The mass of the given volleyball is 0.32 kg.

The momentum is equal to the delivered impulse,

J = m (v- u)

Where,

J - impulsed delivered =  -9.3kg m/s,

u - Initial speed of the ball = 4.2 m/s

v - Final speed of the ball = -24 m/s

m - mass of the object = ?

Put the value in the formula,

Therefore, the mass of the given volleyball is 0.32 kg.

To know more about  impulsed delivered

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The mass of the volleyball is 0.32 kg.

Explanation:

Given that,

Initial speed of the ball, u = 4.2 m/s

Final speed of the ball, v = -24 m/s

The impulse delivered to the ball by the player is -9.3 kg-m/s.

To find,

Mass of the volleyball.

Solution,

The change in momentum of the volleyball is equal to the impulse delivered to the ball. It is given by :

m = 0.32 kg

So, the mass of the volleyball is 0.32 kg.

since you're a real machine, your ama is always less than your ima, because you can never totally eliminate friction.

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