Scientists aboard the international space station are threatened by a 2.8 kg meteor hurtling toward them at 5.4 x 103 m/s. they deploy an enormous rubber band to catch the meteor.

the rubber band stretches 193 m as it stops the meteor and saves the day. how much average force is applied to the meteor?

a) 3.8 x 104 n

b) 5.2 x 104 n

c) 1.3 x 105 n

d) 2.1 x 105 n

e) 4.7 x 106 n

c) 1.3 X 10⁵ N

Explanation:

Step 1: From equation of motion; V² = U² +2as

where, U  and V are initial and final velocity respectively,

a is the acceleration and s is the distance traveled

(5400)² = 0² +2*a*193

a = (5400)²/ (386)

a = 75544.04 m/s²

Step 2: calculate the maximum force applied to the meteor

= 211,523.312 N

Step 3: calculate the average force applied to the meteor

= 105,761.7 N

1.1 X 10⁵ N

The nearest option is C

where are the vectors ?

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