Consider a satellite of mass m1 that orbits a planet of mass m2 in a circle a distance r from the center of the planet. the satellite's mass is negligible compared with that of the planet. indicate whether each of the statements in this problem is true or false. part athe information given is sufficient to uniquely specify the speed, potential energy, and angular momentum of the satellitepart bthe total mechanical energy of the satellite is conserved. part cthe linear momentum vector of the satellite is conserved. part dthe angular momentum of the satellite about the center of the planet is conservedpart ethe equations that express the conservation laws of total mechanical energy and linear momentum are sufficient to solve for the speed necessary to maintain a circular orbit at r without using fâ =maâ .

most voltage drop calculators want the distance between the source and destination. then internally, they double it so both the source and return wires are calculated. but you need to know which distance the calculator uses so you're not half of what you should be or double what you should be.

most circuit breakers will not take a #6 directly, so the electrician will have to splice on a smaller pigtail. you also have to upsize the grounding wire when you upsized the ungrounded (hot) wire (see note in 250.122). this will preclude using most cable assemblies, as a cable with #6 copper will most likely only have a #10 grounding conductor. you need a #6 grounding conductor if the circuit is 20a. a #8 cable is no better, as it will have a #10 grounding conductor too. but most 20a breakers will take a #8 directly.

in your related post, you didn't say what type of load this is. if it is a light or heater, voltage drop won't be a big issue. if this is a motor, the current needs are huge at startup and the voltage drop can pose a problem. if this is a motor, knowing if the motor is under much load during startup will answer the voltage drop effect (a saw is easier to start than a compressor).

learn it on the intertant so you can solve

c)as speed changes, wavelength and frequency change.

everything changes!

what is the question because that is not a question.