You stretch a spring ball system 0.552 m away from its equilibrium point and watch it oscillate. you find that the system's angular frequency is 1.42 rad/sec. what is the maximum speed of the ball?

The maximum speed of ball is 0.784 m/s.

Explanation:

Given that,

Amplitude = 0.552 m

Angular frequency = 1.42 rad/s

We need to calculate the maximum speed of ball

Using formula of speed

Where, A = amplitude

= angular frequency

Put the value into the formula

Hence, The maximum speed of ball is 0.784 m/s.

c. magnitude and direction

the old price per ounce is c/4.

the new price per ounce is c/3.6.

the ratio of the old price to the new one is

(c/4)/(c/3.6) = (c/c)×(3.6/4) = 0.9 . . = 9/10 . . "nine tenths" in either form