Consider the equation y = mt + b, where the dimensions of y is length and the dimensions of t is time, and m and b are constants. when answering question parts in this problem, use the symbols l and t to represent dimensions of length and time, respectively, and use the symbols m and s to represent the si units of meters and seconds, respectively.

SI unit of 'b' is meter (m) while 'm' is m/s.

dimension of 'm' is [L] and 'b' is [L]

Explanation:

consider the equation

y = mt + b      ................ (1)

where y represent the length with a dimension of [L]

also t represent the time with a dimension of [T]

so from (1) we can say that the dimension of mt must equal the dimension of y.

thus

[mt] = [L]

which is [m] = [L]

      the unit of m = meter/ second = m/s

so the S I unit of 'm' is m/s

so [b] = [L]

so, dimension of b is [L]

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14

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