Asatellite orbiting the earth is directly over a point on the equator at 12: 00 midnight every three days. it is not over that point at any time in between.
what is the radius of the satellite's orbit?

the radius of the satellite's orbit  is  r = 8.78×10⁷m

Explanation:

given the time period, T= 3days

converting the time in days to seconds is given as;

time, T=(3*24*60*60) sec

T=259200 sec

from the force relation;

mv²/r = Gm×M/r²

v²=G×M/r (1)

and

V=2pi×r/T

V²=4×pi²×r²/T²

>

from equation  (1) , we have

4×pi²×r²/T²=G×M/r

this becomes;  4×pi²×r³/T² = G×M

r³ = G×M×T²/(4pi²)

r³ = 6.67×10⁻¹¹×(5.97×10²⁴)×(259200)²/(4pi²)

==> r=8.78×10⁷m

radius of the orbit, r=8.78×10⁷ m

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees. 

answer: the metamorphic rocks are formed when they are exposed to high pressure and high temperatures. this happens when one of the earth's plates comes in contact with the other plate by traveling in opposite directions, straight into each other or slipping under one another. the friction that is caused by this activity results in   melting of rocks and when it cools they are known as metamorphic rocks. this process needs a controlled amount of pressure and temperature otherwise it may turn into magma.