Der a string stretched between two supports. the speed of the propagation of transverse waves is 85 m/s, and two successive standing-wave frequencies are 510 hz and 680 hz. a) what is the the order of these two harmonics (first, second, etc)? b) what is the length of the string?

a) 3, 4

b)0.25 m

Explanation:

Given frequency f_1= 510 Hz

and frequency f_2= 680 Hz

v= 85 m/s

and

therefore,

= v/2L

Therefore, length of the string = 0.25 m

510 = 85n/2×0.25

n= 3

therefore order of two harmonics 3,4 .

answer: 0.20

explanation: this can only be the answew because all the other measuremnets are not close

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer