Two identical arrows, one with twice the speed of the other, are fired into a bale of hay. assuming the hay exerts a constant frictional force on the arrows, the faster arrow will penetrate how much farther than the slower arrow? explain

Explanation:

When there is frictional force distance traveled by the arrow is s = (v^2)/(2μ_kg)

v= velocity of the object

μ_k = kinetic friction coefficient

g= acc. due to gravity.

as distance is proportional to square of the speed therefore the faster arrow penetrate a distance 4 times the distance penetrate by slower arrow.

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explanation: