A0.1 kg object initially moving with a velocity of 0.2 m/s makes an elastic head-on collision with a 0.15 kg object initially at rest. what percentage of the original kinetic energy is retained by the 0.10-kg object?

4 %

Explanation:

mass of the object 1, m₁ = 0.1 Kg

initial velocity of object 1,v₁= 0.2 m/s

mass of object 2, m₂ = 0.15 kg

initial speed of the object 2. v₂ = 0 m/s

Kinetic energy retained by the object 1 = ?

using the formula to calculate velocity of the ball after collision

negative sign represent the velocity  is in opposite direction after collision.

Initial KE

final KE

% of KE retained

=

=

= 4 %

the percentage of Kinetic energy retained after collision is equal to   4 %

your answer is yx

hope this

~mia

divide the right side by the left side

0.024÷1.2=0.02 for example