Apoint charge q1 = 3.0 µc is at the origin and a point charge q2 = 6.0 µc is on the x axis at x = 10 m.
(a) find the electric force on charge q2.
12 = mn
(b) find the electric force on q1.
21 = mn
(c) what would your answers for parts (a) and (b) differ if q2 were -6.0 µc?
12 = mn
21 = mn

a.

b.  

c. ,  

Explanation:

Recall that like charged particles repel while unlike charges attract. hence we can conclude that both particles will repel with a force of magnitude

Where .

Substituting values into the above equation we have

Hence the electric force on charge q2 is of magnitude  and the direction is away from q2 in the positive x direction  which can be represented as a vector form as

.

bTo determine the electric force on charge q1, the magnitude remain the same

.. but in the opposite direction which is the negative x-axis

c.if the q2 is -6.0uc, the magnitude of the force will be the same but the direction will be different since both charges are unlike, hence the electric force on q 2 as in (a) above will be towards q1  which can be represented as a vector form as

and for the second case scenario the forc will be directed towards the second charge which can be represented as  

answer

c, on a nylon carpet in a dry area. give me brainliest

explanation: