Question 7 (5 points)
blaine steps onto a ski slope with an angle of 25°. there is a coefficient of kinetic friction of
0.75 between him and the ground. he has a mass of 65 kg.
b. write the expressions for net force in the x and y directions be sure to tilt your axis along the incline
c. calculate the net force and acceleration in the x and y directions

The net force is 165N an the the acceleration is 2.5 m/s2

Explanation: First find the component of force with respect to the angle of inclination.

F = mgsin (theta) = 65 kg x 9.8 m/s2 x sin (25°) = 286N

Next find the value of the normal force

N = mgcos ( theta)

= 65 kg x 9.8m/s² x cos (25°)

= 577N

Substitute the Value of N to find the frictional force.

fk= Coeffiecient of kinetic friction x N

= 0.75x 577 N = 433 N

Solve for the net force through summation of forces.

433 N - 268N = 165N

To find a. Use F= ma

Derive so that a= F/m

a= 165N / 65kg

= 2.54 m/s2

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation:

spare some change and give it to the poor

explanation:

plz : ((