The velocity of a 3.00 kg parti- cle is given by : v = (8.00tiˆ + 3.00t2jˆ) m/s, with time t in seconds. at the instant the net force on the parti- cle has a magnitude of 35.0 n, what are the direction (relative to the positive direction of the x axis) of (a) the net force and (b) the particle's direction of travel?

Part a)

Direction of net force is

Part b)

Direction of the velocity is given as

Explanation:

As we know that the velocity of the particle is given as

now the acceleration is given as

now magnitude of net acceleration is given as

Part a)

Now direction of net force is given as

Part b)

Direction of the velocity is given as

the answer would be c. motion and direction

i hope this : )

the correct choice is a .

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