Astone with a weight of 5.29 n is launched vertically from ground level with an initial speed of 24.0 m/s, and the air drag on it is 0.266 n throughout the flight. what are (a) the maximum height reached by the stone and (b) its speed just before it hits the ground

Answer

given,

weight of the stone , W = 5.29 N

initial speed of the stone, v = 24 m/s

Air drag = 0.266 N

net force acting on the stone when it reaches maximum height is zero

     ma = 5.56 N

  a = 10.3 m/s²

maximum height of the stone

         H = 29.38 m

b) from the maximum height stone will fall as free fall body

using equation of motion

  v² = u ² + 2 a h

   u = 0 m/s

  v = √546.89

  v = 23.39 m/s

speed at which ball hit the ground is equal to 23.39 m/s

it doesn't. it was imagined up in the middle ages.