A(n) 0.47 kg softball is pitched at a speed of 10 m/s. the batter hits it back directly at the pitcher at a speed of 29 m/s. the bat acts on the ball for 0.019 s. what is the magnitude of the impulse imparted by the bat to the ball? answer in units of n â· s.

18.33 Ns

Explanation:

As the pitch back speed has the opposite direction as before, the change in velocity would be

So the change in momentum of the ball would be the product of its velocity change and its mass

This is equals to the impulse acted on the ball by the bat, which is 18.33 Ns

newton's first law of motion

it is called kinetic energy