At t = 15.0 seconds an object with mass 6 kg was observed to have a velocity of ‹ 9, 25, −9 › m/s. at t = 15.1 seconds its velocity was ‹ 18, 17, 21 › m/s. what was the average (vector) net force acting on the object?

Explanation:

Mass = 6 kg

Initial velocity = ‹ 9, 25, −9 › m/s

Initial time = 15.0 s

Final velocity = ‹ 18, 17, 21 › m/s

Final time = 15.1

Change in velocity = ‹ 18, 17, 21 › - ‹ 9, 25, −9 › = ‹ 9, -8, 30 › m/s

Change in time = 15.1 - 15.0 = 0.1 s

Acceleration = Change in velocity ÷ Change in time

Acceleration =  ‹ 9, -8, 30 › ÷ 0.1

Acceleration =  ‹ 90, -80, 300 › m/s²

Force = Mass x acceleration

Force = 6 x ‹ 90, -80, 300 › = ‹ 540, -480, 1800 › N

Average  net force acting on the object is ‹ 540, -480, 1800 › N

answer: the correct answer id option(d).

explanation:

snell's law refraction:

the angle of refraction =

the angle of incidence =

refractive index of air = = 1

refractive index of glycerol = 1.47

from the given options, the most closest answer to 63.72° is 65° of option (d).

the closer the planet is to the sun, the larger the gravity